Решите неравенство (2,5)^2x+1>4/25

$2.5=frac{25}{10}=frac{25:5}{10:2}=frac{5}{2}$
$frac{4}{25}=frac{2*2}{5*5}=(frac{2}{5})^2=(frac{5}{2})^{-2}$
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$(2.5)^{2x+1}>frac{4}{25}$
$(frac{5}{2})^{2x+1}>(frac{5}{2})^{-2}$
$frac{5}{2}>1$
$2x+1>-2$
$2x>-2-1$
$2x>-3$
$x>-3:2$
$>-1.5$
x є $(-1.5;+infty)$