Решите уравнения:
1) sinx+sin2x-cosx=2cos^2x
2)2sin2x-sin^2x=3cos^2x
3)sin4x-cos^4x=-sin^4x
4)1-sin2x=cosx/|cosx|

1.
sin x+sin2x-cos x=2cos^2x

sin x+2sin xcos x-cos x-2cos^2x=0

sin x(1+2cos x)-cos x(1+2cos x)=0

(1+2cos x)(sin x-cos x)=0

left[begin{array}$ 1+2cos x=0  sin x-cos x=0 end{array}right.

left[begin{array}$ 2cos x=-1  mathrm{tg}x-1=0 end{array}right.

left[begin{array}$ cos x=- frac{1}{2}   mathrm{tg}x=1 end{array}right.

left[begin{array}$ x_1=pm frac{2 pi }{3}+2 pi k,  kin Z  x_2= frac{ pi }{4}+ pi n,  nin Z  end{array}right.

2.
2sin2x-sin^2x=3cos^2x

sin^2x-2sin2x+3cos^2x=0

sin^2x-4sin xcos x+3cos^2x=0

mathrm{tg}^2x-4mathrm{tg}x+3=0

(mathrm{tg}x-1)(mathrm{tg}x-3)=0

left[begin{array}$ mathrm{tg}x-1=0  mathrm{tg}x-3=0 end{array}right.

left[begin{array}$ mathrm{tg}x=1  mathrm{tg}x=3 end{array}right.

left[begin{array}$ x_1= frac{ pi }{4}+ pi k,  kin Z   x_2=mathrm{arctg}3+ pi n,  nin Z end{array}right.

3.
sin4x-cos^4x=-sin^4x

sin4x+sin^4x-cos^4x=0

2sin2xcos2x+(sin^2x-cos^2x)(sin^2x+cos^2x)=0

2sin2xcos2x+(-cos2x)cdot1=0

2sin2xcos2x-cos2x=0

cos2x(2sin2x-1)=0

left[begin{array}$ cos2x=0  2sin2x-1=0 end{array}right.

left[begin{array}$ cos2x=0  sin2x=frac{1}{2} end{array}right.
left[begin{array}$ 2x=frac{pi}{2}+pi n  2x=(-1)^kfrac{pi}{6}+pi kend{array}right.

left[begin{array}$ x=frac{pi}{4}+ frac{pi n}{2},  nin Z   x=(-1)^kfrac{pi}{12}+ frac{pi k}{2} ,  kin Z end{array}right.

4.
1-sin2x= frac{cos x}{|cos x|} 

left[begin{array}$ left{begin{array}$ 1-sin2x= frac{cos x}{cos x}   cos x textgreater  0 end{array}right.
  left{begin{array}$ 1-sin2x= frac{cos x}{-cos x}   cos x textless  0 end{array}right.  end{array}right.

left[begin{array}$ left{begin{array}$ 1-sin2x=1   cos x textgreater  0 end{array}right.   left{begin{array}$ 1-sin2x=-1   cos x textless  0 end{array}right.  end{array}right.
left[begin{array}$ left{begin{array}$ -sin2x=0  cos x textgreater  0 end{array}right.  left{begin{array}$ -sin2x=-2  cos x textless  0 end{array}right.  end{array}right.

left[begin{array}$ left{begin{array}$ sin2x=0  cos x textgreater  0 end{array}right.  -sin2x neq -2  right. end{array}right.

left{begin{array}$ sin2x=0  cos x textgreater  0 end{array}right.
left{begin{array}$ 2x=pi n  cos x textgreater  0 end{array}right. 

left{begin{array}$ x= frac{pi n}{2}   cos x textgreater  0 end{array}right. 

x=2 pi n,  nin Z

Оцени ответ
Подпишись на наш канал в телеграм. Там мы даём ещё больше полезной информации для школьников!

Загрузить картинку