4х^2-45 х+123=(х-9)^2
4х²-45х+123=х²-18х+81
3х²-27х+42=0
х²-9х+14=0
х₁,₂=9⁺₋√(81-56) = 9⁺₋5
2 2
х₁=7 х₂=2
Оцени ответ
4х²-45х+123=х²-18х+81
3х²-27х+42=0
х²-9х+14=0
х₁,₂=9⁺₋√(81-56) = 9⁺₋5
2 2
х₁=7 х₂=2