Знатоки логарифмов!!!![12. frac{1}{ log_{8} 0,75} - frac{1}{ log_{6} 0,75} + log_{ sqrt{2} } 0,5=??? 13. frac{ log_{ sqrt[3]{2} } 28}{ log_{32}2 } - frac{ log_{ sqrt[5]{2} } 7}{ log_{8} 2} =??? 12. frac{1}{ log_{8} 0,75} - frac{1}{ log_{6} 0,75} + log_{ sqrt{2} } 0,5=??? 13. frac{ log_{ sqrt[3]{2} } 28}{ log_{32}2 } - frac{ log_{ sqrt[5]{2} } 7}{ log_{8} 2} =???](https://tex.z-dn.net/?f=+12.+%5Cfrac%7B1%7D%7B+log_%7B8%7D+0%2C75%7D+-+%5Cfrac%7B1%7D%7B+log_%7B6%7D+0%2C75%7D+%2B+log_%7B+%5Csqrt%7B2%7D+%7D+0%2C5%3D%3F%3F%3F++13.+%5Cfrac%7B+log_%7B+%5Csqrt%5B3%5D%7B2%7D+%7D+28%7D%7B+log_%7B32%7D2+%7D+-+%5Cfrac%7B+log_%7B+%5Csqrt%5B5%5D%7B2%7D+%7D+7%7D%7B+log_%7B8%7D+2%7D+%3D%3F%3F%3F)
12
1/log(8)0,75=log(0,75)8
1/log(3)0,75=log(0,75)6
log(√2)0,5=-2
log(0,75)8-log(0,75)6-2=log(3/4)4/3 -2=-1-2=-3
13
Перейдем к основанию 2
(log(2)7+2)*log(2)32/log(2)∛2=5(log(2)7+2):1/3=15(log(2)7+2)
log(2)7*log(2)8/log(2)(2^1/5)=3log(2)7:1/5=15log(2)7
15(log(2)7+2)-15log(2)7=15log(2)7+30-15log(2)7=30
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