(2x)/(2x-3) - (3x)/(2x+3) = (15-32x^2)/(4x^2-9)
Решите,пожалуйста :С

$frac{2x}{2x - 3} - frac{3x}{2x+3} = frac{15-32x^2}{4x^2 - 9}$

$2x(2x + 3) - 3x(2x - 3) = 15 - 32x^2$

$15x - 2x^2 = 15 - 32x^2$

$30x^2 + 15x - 15 = 0$

$15(x + 1)(2x - 1) = 0$ $|(:15)$

$(x + 1)(2x - 1) = 0$

$x + 1 = 0 ; 2x - 1 = 0$

$x = -1 ; 2x = 1$

$x1 = -1 x2 = 0.5$