Опубликовано 09.06.2017 по предмету Алгебра от Гость >> <<

log2x=log2/3+log2/5

lg2x-lgx-2=0

Ответ оставил Гость

log2 x -log2 3=log 2(2x-5)Im assuming everthing in the above question is to log of base 2.log2 x -log2 3=log2 (2x-5)Apply logarithm law: log a - log b = log (a/b)log2 (x/3) = log2 (2x-5)Remove the log function from both sides of the equation.x/3 = 2x-5