Решите неравенство (x-3)(2x-3)+6x2>2(2x-3)2

$(x-3)(2x-3)+6x^2 textgreater 2(2x-3)^2$
$8x^2 - 9x + 9 textgreater 8x^2 - 24x + 18$
$8x^2 - 9x + 9 - 8x^2 + 24x - 18 textgreater 0$
$15x - 9 textgreater 0$
$15x textgreater 9$
$x textgreater frac{3}{5}$
$x textgreater 0.6$
$x$ ∈ $(0.6 ; +$ ∞ $)$