2 log 0,5( log2 x)+log2 (log2 x) = -1
-2log(2)(log(2)x)+log(2)(log(2)x)=-1
-log(2)(log(2)x)=-1
log(2)(log(2)x)=1
log(2)x=2
x=4
Оцени ответ
Вход
Регистрация
Задать вопрос
-2log(2)(log(2)x)+log(2)(log(2)x)=-1
-log(2)(log(2)x)=-1
log(2)(log(2)x)=1
log(2)x=2
x=4