Помогите решить!!!)))
4x^2=7x-3.
2x^2+5=-7x

1.) $4 x^{2} -7x+3=0$
$x_{1,2} = frac{7+- sqrt{49-48} }{8}$
$x_{1} = frac{7+1 }{8} =1$
$x_{2} = frac{7-1}{8}= frac{6}{8} = frac{3}{4} =0,75$
2.) $2 x^{2} +7x+5=0$
$x_{1,2} = frac{-7+- sqrt{49-40} }{4}$
$x_{1} = frac{-7+3}{4}= -1$
$x_{2} = frac{-7-3}{4}= - frac{10}{4} =-2,5$