Решите уравнение!!!плз

$sqrt{3x+4}= 2x-x$
$sqrt{3x+4} =x$
esli x<0 netu reshenie
esli x $geq$ 0⇒ $left { {{3x+4 geq 0} atop {3x+47= x^{2} }} right.$
$left { {{3x geq -4} atop { x^{2} -3x-4=0}} right.$
$left { {{x geq -4/3} atop {x=4, x=-1}} right.$ ⇒4,-1
$left { {{x geq 0} atop {x=4, x=-1}} right.$ ⇒x=4