найти точку максимума функции y= $log_{3}$ (11+4x- $x^{2}$ )-2

$y = log_3(11 + 4x - x^2) - 2 (f(g(x))) = frac{dg(x)}{dx}frac{df(g(x))}{dg(x)} = g(x)frac{df(g(x))}{dg(x)} y = (4 - 2x) frac{1}{(11 + 4x - x^2)ln(3)} (4 - 2x) frac{1}{(11 + 4x - x^2)ln(3)} = 0, 11 + 4x - x^2 ne 0, 4 - 2x = 0, -2x = -4, underline{x = 2} 11 + 4x - x^2 = 0, D = 16 + 44 = 60 x_1 = -frac{-4 - sqrt{60}}{2} = 2 + sqrt{15} x_2 = -frac{-4 + sqrt{60}}{2} = 2 - sqrt{15}$