5^(2x-y)=1/5, 5^2x +5^y=6sqrt(5)
cистема
найти х1 и х2

$5x^{2x-y} = 5^{-1}$
$5^{2x} + 5^{y} =6 sqrt{5}$

$2x-y=-1$
$y=2x+1$
$5^{2x} + 5^{2x+1} =6 sqrt{5}$

$y=2x+1$
$5^{2x}(1+ 5) =6 sqrt{5}$

$y=2x+1$
$5^{2x}*6 =6 sqrt{5}$

$y=2x+1$
$5^{2x} = 5^{ frac{1}{2} }$

$2x= frac{1}{2}$
$x= frac{1}{4}$
$y=1.5$

Ответ:(0,25;1,5)