Помогите решить пожалуйста!!!!!Только первый столбец.ЗАРАНЕЕ ОГРОМНОЕ СПАСИБО!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

$(2 sqrt{5}+3 sqrt{2})(sqrt{5}-sqrt{8})=2*5-2 sqrt{40}+3 sqrt{10}-3 sqrt{8}=$
$10-4 sqrt{10}+3 sqrt{10}-3*2 sqrt{2}=10- sqrt{10} -6 sqrt{2}$

$(sqrt{42})^2-(2 sqrt{6}-3 sqrt{2} )^2=42-(4*6-6 sqrt{12}+18 )=$
$=42-24-18+6*2 sqrt{3} =6*2 sqrt{3}$

$( sqrt{11}- 0,5sqrt{22} )(sqrt{11}+ 0,5sqrt{22})=( sqrt{11})^2-(0,5sqrt{22})^2=$
$=11-0,25*22=11(1-0,25*2)=11*0,5=5,5$